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So, when we insert 01-JAN-4712BC, the century byte is 53 and 53 100 = 47, the century we inserted. Because it is negative, we know that it is a BC date. This storage format also allows the dates to be naturally sortable in a binary sense. Since 4712 BC is less than 4710 BC, we d like a binary representation that supports that. By dumping those two dates, we can see that 01-JAN-4710BC is larger than the same day in 4712 BC, so they will sort and compare nicely: ops$tkyte@ORA11GR2> insert into t (x) values 2 ( to_date( '01-jan-4710bc', 3 'dd-mon-yyyybc hh24:mi:ss' ) ); 1 row created. ops$tkyte@ORA11GR2> select x, dump(x,10) d from t; X D --------- -----------------------------------

25-JUN-05 Typ=12 Len=7: 120,105,6,25,13,2,1 01-JAN-12 Typ=12 Len=7: 53,88,1,1,1,1,1 01-JAN-10 Typ=12 Len=7: 53,90,1,1,1,1,1 The month and day bytes, the next two fields, are stored naturally, without any modification. So, June 25 used a month byte of 6 and a day byte of 25. The hour, minute, and second fields are stored in excess-1 notation, meaning we must subtract 1 from each component to see what time it really was. Hence midnight is represented as 1,1,1 in the date field. This 7-byte format is naturally sortable, as you have seen it is a 7 byte field that can be sorted in a binary fashion from small to larger (or vice versa) very efficiently. Additionally, its structure allows for easy truncation, without converting the date into some other format. For example, truncating the date we just stored (25-JUN-2005 12:01:00) to the day (remove the hours, minutes, seconds) is very straightforward. Just set the trailing three bytes to 1,1,1 and the time component is as good as erased. Consider a fresh table, T, with the following inserts: ops$tkyte@ORA11GR2> create table t ( what varchar2(10), x date ); Table created. ops$tkyte@ORA11GR2> insert into t (what, x) values 2 ( 'orig', 3 to_date( '25-jun-2005 12:01:00', 4 'dd-mon-yyyy hh24:mi:ss' ) ); 1 row created. ops$tkyte@ORA11GR2> insert into t (what, x) 2 select 'minute', trunc(x,'mi') from t 3 union all 4 select 'day', trunc(x,'dd') from t 5 union all 6 select 'month', trunc(x,'mm') from t 7 union all 8 select 'year', trunc(x,'y') from t 9 / 4 rows created. ops$tkyte@ORA11GR2> select what, x, dump(x,10) d from t; WHAT -------orig minute day month year X --------25-JUN-05 25-JUN-05 25-JUN-05 01-JUN-05 01-JAN-05 D ----------------------------------Typ=12 Len=7: 120,105,6,25,13,2,1 Typ=12 Len=7: 120,105,6,25,13,2,1 Typ=12 Len=7: 120,105,6,25,1,1,1 Typ=12 Len=7: 120,105,6,1,1,1,1 Typ=12 Len=7: 120,105,1,1,1,1,1

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1. Right-click a cell in the pivot table, and then choose PivotTable Options. 2. On the Layout & Format tab, in the Layout section, add a check mark to Merge and Center Cells with Labels. 3. Click OK, to close the dialog box.

To truncate that date down to the year, all the database had to do was put 1s in the last 5 bytes a very fast operation. We now have a sortable, comparable DATE field that is truncated to the year level, and we got it as efficiently as possible.

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A question I am frequently asked is, How do I add time to or subtract time from a DATE type For example, how do you add one day to a DATE, or eight hours, or one year, or one month, and so on. There are three techniques you ll commonly use: Simply add a NUMBER to the DATE. Adding 1 to a DATE is a method to add 1 day. Adding 1/24 to a DATE therefore adds 1 hour and so on. You may use the INTERVAL type, as described below, to add units of time. INTERVAL types support two levels of granularity: years and months, or days/hours/minutes/seconds. That is, you may have an interval of so many years and months or an interval of so many days, hours, minutes and seconds. Add months using the built-in ADD_MONTHS function. Since adding a month is generally not as simple as adding 28 to 31 days, a special purpose function was implemented to facilitate this.

Table 12-3 demonstrates the techniques you would use to add (or subtract, of course) N units of time to a date. Table 12-3. Adding Time to a Date

This setting automatically centers the Row Labels vertically and horizontally. The subtotals for the Row Labels, and the Grand Total row label are also centered vertically and horizontally.

DATE + n/24/60/60 DATE + n/86400 DATE + NUMTODSINTERVAL(n,'second')

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